0=x^2-10x-600

Solution for 0=x^2-10x-600 equation:

0=x^2-10x-600

We move all terms to the left:

0-(x^2-10x-600)=0

We add all the numbers together, and all the variables

-(x^2-10x-600)=0

We get rid of parentheses

-x^2+10x+600=0

We add all the numbers together, and all the variables

-1x^2+10x+600=0

a = -1; b = 10; c = +600;
Δ = b2-4ac
Δ = 102-4·(-1)·600
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*-1}=\frac{-60}{-2}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*-1}=\frac{40}{-2}
=-20
$